4.2x^2-35=0

Solution for 4.2x^2-35=0 equation:

4.2x^2-35=0

a = 4.2; b = 0; c = -35;
Δ = b2-4ac
Δ = 02-4·4.2·(-35)
Δ = 588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{588}=\sqrt{196*3}=\sqrt{196}*\sqrt{3}=14\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{3}}{2*4.2}=\frac{0-14\sqrt{3}}{8.4}
=-\frac{14\sqrt{3}}{8.4}
=-\frac{7\sqrt{3}}{4.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{3}}{2*4.2}=\frac{0+14\sqrt{3}}{8.4}
=\frac{14\sqrt{3}}{8.4}
=\frac{7\sqrt{3}}{4.2}
$